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自学教程:C++ solution函数代码示例

51自学网 2021-06-03 08:06:54
  C++
这篇教程C++ solution函数代码示例写得很实用,希望能帮到您。

本文整理汇总了C++中solution函数的典型用法代码示例。如果您正苦于以下问题:C++ solution函数的具体用法?C++ solution怎么用?C++ solution使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。

在下文中一共展示了solution函数的29个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的C++代码示例。

示例1: main

int main(int argc, char *argv[]){	QString ampFile("../example_data/amplitude_199x199_double.raw");	QString phaFile("../example_data/phase_199x199_double.raw");	QString solFile("../example_data/solution_199x199_double.raw");	QSize rawSize(199,199);	int sz = rawSize.width() * rawSize.height();	QFile amplitude(ampFile);	if (!amplitude.open(QIODevice::ReadOnly))	{		qDebug() << "amplitude file not found" << ampFile;		return -1;	}	double* amp = new double[sz];	amplitude.read((char*)amp, sz * sizeof(amp[0]));		amplitude.close();	QFile phase(phaFile);	if (!phase.open(QIODevice::ReadOnly))	{		qDebug() << "phase file not found" << phaFile;		return -1;	}	double* pha = new double[sz];	phase.read((char*)pha, sz * sizeof(pha[0]));	phase.close();	GSATracking up;	up.SetBranchCutMode(GSATracking::AMPLITUDETRACING); // aplitude tracking mode	up.SetCutsDilate(7); // dilatation kernel radius	up.SetInterpolate(true); // interpolation enabled	up.SetWeightedInterpolation(true); // amplitude based weighted interpolation	double* sol = up.UnWrapp(pha, amp, rawSize);	QFile solution(solFile);	solution.open(QIODevice::WriteOnly);	solution.write((char*)sol, sz * sizeof(sol[0]));	solution.close();	delete amp;	delete pha;	qDebug() << "positive residues:" << up.PositiveResidueCount();	qDebug() << "negative residues:" << up.NegativeResidueCount();	qDebug() << "solution file created:" << solFile;	qDebug() << endl << "press any key";	std::cin.get();	return 0;}
开发者ID:Lukas-kV,项目名称:HoloPhaser,代码行数:58,


示例2: quadrature_formula

Report ElasticProblem2DOnCellV2<dim>::calculate_cells_stress (){    cells_stress .clear ();    dealii::QGauss<dim> quadrature_formula(2);    dealii::FEValues<dim> fe_values (finite_element, quadrature_formula,            dealii::update_gradients |             dealii::update_quadrature_points | dealii::update_JxW_values);    const uint8_t dofs_per_cell = finite_element.dofs_per_cell;    const uint8_t num_quad_points = quadrature_formula.size();    typename dealii::DoFHandler<dim>::active_cell_iterator cell =        this->domain.dof_handler.begin_active();    typename dealii::DoFHandler<dim>::active_cell_iterator endc =        this->domain.dof_handler.end();    std::vector<unsigned int> local_dof_indices (dofs_per_cell);    size_t cell_num = 0;    for (; cell != endc; ++cell)    {            fe_values .reinit (cell);            dbl area = 0.0;            for(st i = 0; i < num_quad_points; ++i)                area += fe_values.JxW(o);            dbl mat_id = cell->material_id();                                std::array<dbl,2> deform;                    for (auto i : {x, y})                     {                        deform[i][j] = 0.0;                        for(auto i : {1, 2, 3, 4})                        {                                                dbl summ = 0.0;                            for (size_t q_point = 0; q_point < num_quad_points; ++q_point)                                summ +=                                     fe_values.shape_grad (n, q_point)[i] *                                    fe_values.JxW(q_point);                            deform[i] +=                                 solution(cell->vertex_dof_index(n, 0)) *                                 summ;                        };                        deform[i] /= area;                                        };    };    REPORT_USE(             Report report;            report.result = true;            _return (report););
开发者ID:evil-is-good,项目名称:primat-projects,代码行数:58,


示例3: fill_costs

//Solves the puzzlevoid puzzle::solve(){        std::cout << "Finding edge costs..." << std::endl;    fill_costs();    std::vector<match_score>::iterator i= matches.begin();    PuzzleDisjointSet p((int)pieces.size());      //You can save the individual pieces with their id numbers in the file name//If the following loop is uncommented.//    for(int i=0; i<pieces.size(); i++){//        std::stringstream filename;//        filename << "/tmp/final/p" << i << ".png";//        cv::imwrite(filename.str(), pieces[i].full_color);//    }        int output_id=0;    while(!p.in_one_set() && i!=matches.end() ){        int p1 = i->edge1/4;        int e1 = i->edge1%4;        int p2 = i->edge2/4;        int e2 = i->edge2%4;        //Uncomment the following lines to spit out pictures of the matched edges...//        cv::Mat m = cv::Mat::zeros(500,500,CV_8UC1);//        std::stringstream out_file_name;//        out_file_name << "/tmp/final/match" << output_id++ << "_" << p1<< "_" << e1 << "_" <<p2 << "_" <<e2 << ".png";//        std::vector<std::vector<cv::Point> > contours;//        contours.push_back(pieces[p1].edges[e1].get_translated_contour(200, 0));//        contours.push_back(pieces[p2].edges[e2].get_translated_contour_reverse(200, 0));//        cv::drawContours(m, contours, -1, cv::Scalar(255));//        std::cout << out_file_name.str() << std::endl;//        cv::imwrite(out_file_name.str(), m);//        std::cout << "Attempting to merge: " << p1 << " with: " << p2 << " using edges:" << e1 << ", " << e2 << " c:" << i->score << " count: "  << output_id++ <<std::endl;        p.join_sets(p1, p2, e1, e2);        i++;    }        if(p.in_one_set()){        std::cout << "Possible solution found" << std::endl;        solved = true;        solution = p.get(p.find(1)).locations;        solution_rotations = p.get(p.find(1)).rotations;                for(int i =0; i<solution.size[0]; i++){            for(int j=0; j<solution.size[1]; j++){                int piece_number = solution(i,j);                pieces[piece_number].rotate(4-solution_rotations(i,j));            }        }                    }            }
开发者ID:grevutiu-gabriel,项目名称:PuzzleSolver,代码行数:58,


示例4: main

void main(){	long int a;	int X,Y,D;	scanf("%d %d %d",&X,&Y,&D);	a=solution(X,Y,D);	printf("Ans: %li/n /r",a);}
开发者ID:ChaitraVenk,项目名称:Hello,代码行数:9,


示例5: main

int main(void){  int16_t *array = malloc(5 * sizeof(int16_t));  for(size_t i = 0; i < 5; i++) array[i] = i;  array = solution(array, 5, 5);  for(size_t i = 0; i < 5; i++) printf("%d ", array[i]);}
开发者ID:MrPlatwnas,项目名称:Codility,代码行数:9,


示例6: main

int main(int argc, const char * argv[]){    int A[] = {9,3,9,3,9,7,9};    int N = 7;        printf("%d/n", solution(A,N));        return 0;}
开发者ID:AlexTerekhoff,项目名称:Codility-lessons,代码行数:9,


示例7: main

int main() {    int M, n;    scanf("%d", &M);    while (M--) {        scanf("%d", &n);        printf("%d/n", solution(n));    }    //system("pause");    return 0;}
开发者ID:scofield7419,项目名称:algorithms,代码行数:10,


示例8: TEST

TEST(matrix3, GetTranslationMatrix){	Vector2 v1(3, -7);	Matrix3 m = m.GetTranslationMatrix(v1);	Matrix3 solution(		1, 0, 3,		0, 1, -7,		0, 0, 1);	EXPECT_TRUE(m == solution);}
开发者ID:TheCapleGuy,项目名称:MathLib,代码行数:10,


示例9: _auxs

voidAuxiliarySystem::computeNodalVars(ExecFlagType type){  std::vector<AuxWarehouse> & auxs = _auxs(type);  // Do we have some kernels to evaluate?  bool have_block_kernels = false;  for (std::set<SubdomainID>::const_iterator subdomain_it = _mesh.meshSubdomains().begin();      subdomain_it != _mesh.meshSubdomains().end();      ++subdomain_it)  {    have_block_kernels |= (auxs[0].activeBlockNodalKernels(*subdomain_it).size() > 0);  }  Moose::perf_log.push("update_aux_vars_nodal()","Solve");  PARALLEL_TRY {    if (have_block_kernels)    {      ConstNodeRange & range = *_mesh.getLocalNodeRange();      ComputeNodalAuxVarsThread navt(_mproblem, *this, auxs);      Threads::parallel_reduce(range, navt);      solution().close();      _sys.update();    }  }  PARALLEL_CATCH;  Moose::perf_log.pop("update_aux_vars_nodal()","Solve");  //Boundary AuxKernels  Moose::perf_log.push("update_aux_vars_nodal_bcs()","Solve");  PARALLEL_TRY {    // after converting this into NodeRange, we can run it in parallel    ConstBndNodeRange & bnd_nodes = *_mesh.getBoundaryNodeRange();    ComputeNodalAuxBcsThread nabt(_mproblem, *this, auxs);    Threads::parallel_reduce(bnd_nodes, nabt);    solution().close();    _sys.update();  }  PARALLEL_CATCH;  Moose::perf_log.pop("update_aux_vars_nodal_bcs()","Solve");}
开发者ID:MatthewWilliamNoble,项目名称:moose,代码行数:43,


示例10: addConfig

intaddConfig(Config config, struct puzzle *back){  unsigned hashvalue;  struct puzzle *newpiece;  struct puzzlelist *newlistentry;  hashvalue = hash(config);  newpiece = hashtable[hashvalue % HASHSIZE];  while (newpiece != NULL) {    if (newpiece->hashvalue == hashvalue) {      int i, j;      for (i = 0; i < WIDTH; i++) {        for (j = 0; j < HEIGHT; j++) {          if (convert[(int)config[j][i]] !=            convert[(int)newpiece->pieces[j][i]])            goto nomatch;        }      }      return 0;    }  nomatch:    newpiece = newpiece->next;  }  newpiece = (struct puzzle *) malloc(sizeof(struct puzzle));  newpiece->next = hashtable[hashvalue % HASHSIZE];  newpiece->hashvalue = hashvalue;  memcpy(newpiece->pieces, config, HEIGHT * WIDTH);  newpiece->backptr = back;  newpiece->solnptr = NULL;  hashtable[hashvalue % HASHSIZE] = newpiece;  newlistentry = (struct puzzlelist *) malloc(sizeof(struct puzzlelist));  newlistentry->puzzle = newpiece;  newlistentry->next = NULL;  if (lastentry) {    lastentry->next = newlistentry;  } else {    puzzles = newlistentry;  }  lastentry = newlistentry;  if (back == NULL) {    startPuzzle = newpiece;  }  if (solution(config)) {    solidifyChain(newpiece);    return 1;  }  return 0;}
开发者ID:GustavoMOG,项目名称:efltk,代码行数:55,


示例11: main

int main() {    printf("Answer: %lu/n", solution());    timestamp_t t0 = get_timestamp();    for (int i = 0; i < 3; ++i) {        solution();    }    timestamp_t t1 = get_timestamp();    double t_elapsed = (t1 - t0) / 1000000.0L / 3;    if (t_elapsed < 3) {         int run_time = 10;         unsigned long long n_iters = run_time / t_elapsed;         timestamp_t t0 = get_timestamp();         for (int i = 0; i < n_iters; ++i) {             solution();         }         timestamp_t t1 = get_timestamp();         t_elapsed = (t1 - t0) / 1000000.0L / n_iters;    }    double exp_t = log10(t_elapsed);    if (exp_t > 0) {        printf("Average Duration: %.3g s/n", t_elapsed);    } else if (exp_t > -3) {        printf("Average Duration: %.3Lg ms/n", t_elapsed * 1000.0L);    } else if (exp_t > -6) {        printf("Average Duration: %.3Lg 
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