这篇教程C++ writelines函数代码示例写得很实用,希望能帮到您。
本文整理汇总了C++中writelines函数的典型用法代码示例。如果您正苦于以下问题:C++ writelines函数的具体用法?C++ writelines怎么用?C++ writelines使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。 在下文中一共展示了writelines函数的30个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的C++代码示例。 示例1: mainint main(int argc, char *argv[]){ int ret = 0; int nlines = 0; /* number of input lines read */ int n = N; printf("/n This program prints the last n lines from the input"); printf("/n/t nis 10 by default but we can change it by running the program with %s -n new_n_value/n", argv[0]); if( (nlines = readlines(lineptr, MAXLINES)) > 0) { printf("/n"); if (argc == 1) { ///printing the last 10 lines from the input writelines(lineptr, nlines, n); } else if (argc == 3) { /// printing the last n lines from the input writelines(lineptr, nlines, atoi(argv[2])); } else printf("erorr for command line arguments"); } return ret; }
开发者ID:danadorneanu,项目名称:portofolio,代码行数:28,
示例2: mainint main(int argc, char *argv[]){ int ret = 0; int nlines = 0; /* number of input lines read */ printf("/ntesting atoi %d", atoi("123")); printf("/ntesting atoi %d", atoi("23")); printf("/nThis program alphabetically sorts the input lines/nGive me some input/n"); if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { printf("/n/t The lines in unsorted order are:/n"); writelines(lineptr, nlines); if (argc == 1) { qsort(lineptr, nlines, sizeof(char *), cmpstringp); printf("/n/t The lines sorted alphabetically in growing order are:/n"); writelines(lineptr, nlines); } else if (argc == 2) { if(!strcmp(argv[1], "-r")) { qsort(lineptr, nlines, sizeof(char *), cmpstringp_inv); printf("/n/t The lines sorted alphabetically in reversed order are:/n"); writelines(lineptr, nlines); } if(!strcmp(argv[1], "-n")) { qsort(lineptr, nlines, sizeof(char *), numcmp); printf("/n/t The lines sorted in num order are:/n"); writelines(lineptr, nlines); } } else if (argc == 3) { if( (!strcmp(argv[1], "-r") && (!strcmp(argv[2], "-n"))) || ((!strcmp(argv[1], "-n")) && (!strcmp(argv[2], "-r"))) ) qsort(lineptr, nlines, sizeof(char *), numcmp_inv); printf("/n/t The lines sorted in reversed num order are:/n"); writelines(lineptr, nlines); } else { printf("/n error: wrong comand line parameters /n"); return ret + 1; } return ret; } else { printf("error: input too big to sort/n"); return ret + 1; } return ret;}
开发者ID:danadorneanu,项目名称:portofolio,代码行数:60,
示例3: mainint main(void){ int nlines; /* number of input lines read */ if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { writelines(lineptr, nlines); quicksort(lineptr, 0, nlines -1); writelines(lineptr, nlines); return 0; } else { printf("error: input too big to sort/n"); return -1; }}
开发者ID:tingxueren,项目名称:cstudy,代码行数:15,
示例4: mainmain(int argc, char *argv[]){ int nlines; /* number of read lines */ int ignorecase, reverse, numeric; /* 1, if numerical comparison */ ignorecase = reverse = numeric = 0; char c; while (--argc > 0 && (*++argv)[0] == '-') while (c = *++argv[0]) { switch (c) { case 'n': numeric = 1; break; case 'r': reverse = 1; break; case 'i': ignorecase = 1; break; case 'h': printf("Usage: "PROG" [-nird] /"STDIN/"/n"); return 0; break; default: printf(PROG": illegal option %c/n", c); argc = 0; return 1; break; } if (c == '/0') break; } if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { printf("/nBefore sort:/n"); writelines(lineptr, nlines); int (*pf) (const char *, const char *) = ignorecase ? _strcasecmp : _strcmp; qsort((void **) lineptr, 0, nlines - 1, (int (*)(void *, void *))(numeric ? numcmp : pf), reverse); printf("/nAfter sort:/n"); writelines(lineptr, nlines); return 0; } else { printf("input too bit to sort/n"); return 1; }}
开发者ID:taras-ko,项目名称:c,代码行数:48,
示例5: main/* sort input lines */main(int argc, char *argv[]){ int nlines,reverse = 1; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */ while(--argc > 0 && (*++argv)[0] == '-') { int c; while( c = *++argv[0] ) { switch(c) { case 'n': numeric = 1; break; case 'r': reverse = -1; break; } } } if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsort((void**) lineptr, 0, nlines-1, reverse, (int (*)(void*,void*))(numeric ? numcmp : strcmp)); writelines(lineptr, nlines); getchar(); return 0; } else { printf("input too big to sort/n"); return 1; }}
开发者ID:Qinhaixiang,项目名称:KRBook,代码行数:32,
示例6: mainint main(int argc, char *argv[]) { int nlines, numeric = 0, reverse = 0; while (*++argv) { if (**argv == '-') { while (*++*argv) { if (**argv == 'r') { reverse = 1; } if (**argv == 'n') { numeric = 1; } } } else { printf("format error: sort -rn/n"); exit(0); } } if (argc > 1 && strcmp(argv[1], "-n") == 0) { numeric = 1; } if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsortx((void **)lineptr, 0, nlines-1, (int (*)(void *, void *))(numeric ? numcmp : strcmp)); writelines(lineptr, nlines, reverse); return 0; } else { printf("error: inut too big to sort/n"); return -1; }}
开发者ID:devilTian,项目名称:Fragment,代码行数:31,
示例7: mainint main(int argc, char **argv){ // save lines inputed in a pointer array int lines, revert, fold, directory; fold = directory = 0; revert = 1; // Use dynamic allocation memory: Umm... maybe in the next time. char alloc[ALLOCSIZE]; char *ptarr[MAXLINES]; // Check argument while (--argc > 0 && (*++argv)[0] == '-') { char *p; p = argv[0]; if (!setopt(p,&directory, &revert, &fold)) { youneedhelp(); return EXIT_FAILURE; } } while ((lines = readlines(ptarr, MAXLINES, alloc)) > 0) { // any pointer can be cast to void * and back again without loss of information. int (*comp)(void *, void *, int); // Is it too long :( comp = (int (*)(void *, void *, int))(directory ? strdfcmp : strfcmp); // sorting use quick sort algorithm. myqsort((void**)ptarr, 0, lines-1, comp, fold, revert); writelines(ptarr,lines); } return EXIT_SUCCESS;}
开发者ID:ducanhng,项目名称:ctuto,代码行数:34,
示例8: main/* sort input lines */int main(int argc, char **argv){ int nlines; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */#ifndef ORIGINAL int reverse = 0; char lineptr2[MAXLINES][MAXLEN]; nlines = MAXLINES; while (nlines-- > 0) { lineptr[nlines] = lineptr2[nlines]; } while (*++argv) { if (strcmp(*argv, "-r") == 0) { reverse = 1; } else if (strcmp(*argv, "-n") == 0) { numeric = 1; } }#else if (argc > 1 && strcmp(argv[1], "-n") == 0) { numeric = 1; }#endif if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsort((void **)lineptr, 0, nlines - 1, (int (*)(void *, void*))(numeric == 1 ? numcmp : strcmp)); writelines(lineptr, nlines, reverse); return 0; } else { printf("error: input too big to sort/n"); return 1; }}
开发者ID:liudongmiao,项目名称:tcpl,代码行数:36,
示例9: main/*Program starts*/int main(int argc, char *argv[]){ int nlines; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */ int reverse = 0; /* 1 if reverse sort */ int foldcase = 0; /* 1 if folding case */ int dirorder = 0; /* 1 if "directory order" comparision */ /* storage supplied by main */ char linebuf[MAXLEN * MAXLINES]; /* check options */ if (argc > 1) if (getopt(argv, &numeric, &reverse, &foldcase, &dirorder) == -1) return 2; /* read - sort - write */ if ((nlines = readlines(lineptr, linebuf, MAXLINES)) > 0) { qsort1((void **) lineptr, 0, nlines -1, (int (*)(void *, void *))(numeric ? numcmp : (foldcase ? strcasecmp : strcmp)), reverse, dirorder); writelines(lineptr, nlines); return 0; } else { printf("error: input too big to sort/n"); return 1; } return 0;}
开发者ID:1sps,项目名称:knr,代码行数:33,
示例10: mainint main( int argc, char *argv[]){ int nlines; /* number of input lines read */ int c, numeric = 0, reverse = 0; /*flags for options */ while(--argc > 0 && (*++argv)[0] == '-') while(c = *++argv[0]) switch(c) { case 'n': numeric = 1; break; case 'r': reverse = 1; break; default: printf("sort: illegal option %c/n",c); break; } if((nlines = readlines(lineptr,MAXLINES)) >= 0) { qsort((void **) lineptr, 0, nlines-1, (int (*)(void*,void*))(numeric ? numcmp : strcmp),reverse); writelines(lineptr,nlines); return 0; } else { printf("input too big to sort /n"); return 1; }}
开发者ID:bmkessler,项目名称:The_C_Programming_Language,代码行数:28,
示例11: main/* sort input lines */int main(int argc, char *argv[]){ char *lineptr[MAXLINES]; /* pointers to text lines */ int nlines; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */ /* If the optional argument -n is given, it will sort the input lines * numerically instead of lexicographically. */ if (argc > 1 && strCmp(argv[1], "-n") == 0) numeric = 1; /* lineptr是一个指针,指向的变量类型是char *, 则lineptr对应的数据类型是 * char **,后面一个 * 表示这是一个指针,前面的char * 表示指针指向的类型 * 是 char *; 所以要下面使用 void ** 来进行强制转换,而不是 void * */ if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsort((void **)lineptr, 0, nlines - 1, (int (*)(const void*, const void*))(numeric ? numcmp : strCmp)); printf("-------------After sort----------/n"); writelines(lineptr, nlines); return 0; } else { printf("error: input too big to sort/n"); return 1; }}
开发者ID:forkhope,项目名称:c,代码行数:28,
示例12: mainint main(int argc, char **argv){ int nlines; unsigned opts = 0; while(*++argv != NULL) { if((*argv)[0] == '-') { while(*++*argv) { switch(**argv) { case 'n': opts |= OPT_NUMERIC; break; case 'r': opts |= OPT_REVERSE; break; } } } } if((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsort_lomuto((void **) lineptr, 0, nlines-1, (int (*)(void *, void *))(opts & OPT_NUMERIC ? numcmp : strcmp), opts); writelines(lineptr, nlines); return 0; } else { printf("Input too large to sort./n"); return 1; }}
开发者ID:zastari,项目名称:Worked_Solutions,代码行数:30,
示例13: mainint main(int argc, char *argv[]){ char numeric = 0; char reverse = 0; char caseInsensitive = 0; int nlines; char lines[MAXLINES*MAXLEN]; int arg = 1; while(arg < argc){ if(strcmp(argv[arg], "-n") == 0){ numeric = 1; } else if(strcmp(argv[arg], "-r") == 0){ reverse = 1; } else if(strcmp(argv[arg], "-f") == 0){ caseInsensitive = 1; } arg++; } if((nlines = readlines(linesptr, lines, MAXLINES)) >= 0){ qsort2((void **) linesptr, 0, nlines-1, (numeric ? numcmp : caseInsensitive ? strcasecmp : strcmp)); writelines(linesptr, nlines, reverse); return 0; } else { printf("input too big to sort/n"); return 1; }}
开发者ID:bnjzer,项目名称:c,代码行数:29,
示例14: mainint main(int argc, char *argv[]){ int nlines; int numeric = 0; int asc = 1; int i; while (argc-- > 1) { if (strcmp(argv[argc], "-n") == 0) numeric = 1; else if (strcmp(argv[argc], "-r") == 0) asc = -1; } if (argc > 1 && strcmp(argv[1], "-n") == 0) numeric = 1; if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { myqsort((void **) lineptr, 0, nlines-1, (int (*)(void*,void*))(numeric ? numcmp : strcmp), asc); writelines(lineptr, nlines); return 0; } else { printf("input too big to sort/n"); return 1; }}
开发者ID:jlegoff,项目名称:misc,代码行数:25,
示例15: implvoid impl( char * path ){ FILE * fp = fopen(path,"rb"); if( !fp ) { perror(path); return; } int nlines = 0; char * lineptr[MAXLINES]; if( (nlines = readlines( fp, lineptr, MAXLINES)) >= 0 ) { int (*comparator)(void*,void*) = IS_NUMERIC ? (IS_NUMERIC_FIELD ? ((int(*)(void*,void*))numfieldcmp) : ((int(*)(void*,void*))numcmp) ) : IS_DICTIONARY ? (IS_DICTIONARY_FIELD ? ((int(*)(void*,void*))strDirectoryOrderFieldcmp) : ((int(*)(void*,void*))strDirectoryOrdercmp) ) : IS_CASE_INSENSITIVE ? (IS_CASE_INSENSITIVE_FIELD ? ((int(*)(void*,void*))strcaseFieldcmp) : ((int(*)(void*,void*))strcasecmp) ) : (int(*)(void*,void*))strcmp; qsort_ex_5_14( (void **)lineptr, 0, nlines - 1, comparator); writelines( lineptr, nlines); } else { printf("Error, too many lines to sort, max is %d/n",MAXLINES); return; } fclose(fp);}
开发者ID:markmontymark,项目名称:knr-c,代码行数:31,
示例16: mainint main(int argc, char *argv[]){ int nlines, i; int numeric = 0; int sort_dir = ASC; /* positive 1 for ascending, negative 1 for descending */ /* check command line arguments and toggle flags*/ for(i = 1; i < argc; i++){ if(*argv[i] == '-'){; if(strchr(argv[i], 'n') != NULL){ numeric = 1; } if(strchr(argv[i], 'r') != NULL){ sort_dir = DESC; } } } if((nlines = readlines(lineptr, MAXLINES)) >= 0){ sm_qsort((void**) lineptr, 0, nlines-1, (int (*)(const void*, const void*, const int))(numeric ? numcmp : sm_strcmp), sort_dir); writelines(lineptr, nlines); return 0; } else{ printf("input too big to sort/n"); return 1; }}
开发者ID:stephenmerendino,项目名称:k-r-exercises,代码行数:29,
示例17: main// sort input linesint main(int argc, char *argv[]) { int nlines; int (*cmpfunc)(void*,void*) = (int (*)(void*,void*)) strcmp; int direction = 1; // sorting normally (low -> high) while (--argc > 0 && (*++argv)[0] == '-') while (*++argv[0]) switch (*argv[0]) { case 'n': // numerically cmpfunc = (int (*)(void*,void*)) numcmp; break; case 'r': // reverse direction = -1; break; case 'f': // fold cases cmpfunc = (int (*)(void*,void*)) strcmpf; break; default: printf("Unknown option '%c'/n", *argv[0]); argc = 0; break; } if (argc < 0) { printf("Usage: sortlines [-n] [-r] [-f]/n"); return 1; } else if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsortf((void **) lineptr, 0, nlines-1, cmpfunc, direction); writelines(lineptr, nlines); return 0; } else { printf("input too big to sort/n"); return 1; }}
开发者ID:Prince781,项目名称:k-and-r,代码行数:35,
示例18: mainint main(int argc, char *argv[]){ int nlines; char linestor[MAXSTOR]; int print_n = 10; if (argc == 1) print_n = 10; else if (argc == 2 && (*++argv)[0] == '-') { print_n = atoi(argv[0] + 1); if (print_n > MAXLINES && print_n <= 0) { print_n = 10; } } else printf("Usage: tail [-n]/n"); if ((nlines = readlines(lineptr, linestor, MAXLINES)) >= 0) { if (nlines < print_n) print_n = nlines; printf("/n/nThe last %d lines:/n", print_n); writelines(lineptr, nlines, print_n); return 0; } else { printf("error: input too big to tail/n"); return 1; }}
开发者ID:cloverstd,项目名称:The-C-Programming-Language,代码行数:35,
示例19: mainint main(int argc, char *argv[]){ int opt; int reverse = 0; int fold = 0; int total = -1; char *lines[MAXLINES]; while ((opt = getopt(argc, argv, "rhf")) != -1) { switch (opt) { case 'r': reverse = 1; break; case 'f': fold = 1; break; case 'h': usage(argv[0]); break; default: fprintf(stderr, "unknow opt: %c/n", opt); break; } } if ((total = readlines(lines, MAXLINES)) >= 0) { if (fold) { qsort_c(lines, 0, total, charcmp); } else { qsort_c(lines, 0, total, strcmp); } writelines(lines, total + 1, reverse); } exit(0);}
开发者ID:peterlintang,项目名称:c-language,代码行数:35,
示例20: mainint main(int argc, char *argv[]){ int nlines; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */ int i; for (i = 1; i < argc ; i++) { if (*argv[i] == '-') { switch (*(argv[i] + 1)) { case 'n': numeric = 1; break; case 'r': order = 1; break; case 'f': fold = 1; default: break; } } } if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { q_sort((void**)lineptr, 0, nlines-1,(int(*)(void*, void*))(numeric ? numcmp : (fold ? fstrcmp : strcmp)), order); printf("/nResult:/n======/n"); writelines(lineptr, nlines); return 0; } else { printf("error: input too big to sort/n"); return 1; }}
开发者ID:sushithbalu,项目名称:KandR2-solutions,代码行数:33,
示例21: main/* sort input lines */int main(int argc, char *argv[]){ int nlines; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */ int reverse = 0; /* 1 if reverset sort */ getop(argc, argv, &numeric, &reverse); if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { if (numeric){ if (reverse) { _qsort((void**) lineptr, 0, nlines - 1, (int (*) (void *, void *)) rnumcmp); } else { _qsort((void**) lineptr, 0, nlines - 1, (int (*) (void *, void *)) numcmp); } } else { if (reverse) { _qsort((void**) lineptr, 0, nlines - 1, (int (*) (void *, void *)) rstrcmp); } else { _qsort((void**) lineptr, 0, nlines - 1, (int (*) (void *, void *)) strcmp); } } writelines (lineptr, nlines); return 0; } else { printf ("input too big to sort/n"); return 1; }}
开发者ID:Nobody-7,项目名称:The-C-Programming-Language,代码行数:31,
示例22: mainint main(int argc, char *argv[]) { char *lineptr[MAX]; int nlines = readlines(lineptr, MAX); assert(nlines == 4); assert(!strcmp(lineptr[0], "first line")); assert(!strcmp(lineptr[3], "last line")); printf("--- start write lines ---/n"); writelines(lineptr, nlines);}
开发者ID:fool2fish,项目名称:the-c-programming-language-exercise-answers,代码行数:10,
示例23: mainint main(){ char *lines[MAXLINE]; int number; if( (number = readlines(lines, MAXLINE)) >= 0){ qsort(lines, 0, number - 1); writelines(lines, number); }else{ printf("error: input too big to sort/n"); return 1; }}
开发者ID:ZeyuMi,项目名称:Cpractices,代码行数:11,
示例24: mainint main(){ int nlines; if((nlines = readlines(lineptr,MAXLINE)) >=0 ){ qsort(lineptr,0,nlines-1); writelines(lineptr,nlines); return 0; }else{ printf("error"); return 1; }}
开发者ID:tirozhang,项目名称:C,代码行数:11,
示例25: mainint main (int argc, char *argv[]){ int c, nlines; while (--argc > 0 && (*++argv)[0] == '-') while ((c = *++argv[0])) switch (c) { case 'd': directory = !0; break; case 'f': fold = !0; break; case 'n': numeric = !0; break; case 'r': reverse = -1; break; default: printf("Error: Illegal option '%c'./n", c); return 1; } if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsort((void **) lineptr, 0, nlines -1, (int (*)(void *, void *)) (numeric ? numcmp : strcmp)); writelines(lineptr, nlines); return 0; } else { printf("Error: Input too big to sort!/n"); return 1; }}
开发者ID:KiroShin,项目名称:tcpl,代码行数:54,
示例26: mainint main(){ int nlines; if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { qsort(lineptr, 0, nlines - 1); writelines(lineptr, nlines); return 0; } else { printf("error: input too big to sort/n"); return 1; }}
开发者ID:WebFeng,项目名称:learn_c,代码行数:12,
示例27: main/* sort input lines */int main(int argc, char *argv[]){ int i, j, c, nlines; /* number of input lines read */ int numeric = 0; /* 1 if numeric sort */ int reverse = 0; /* 1 if decreasing sort*/ int foldul = 0; /* 1 fold upper and lower case together */ for (i = 1; i < argc; i++) { if ((*++argv)[0] == '-') { for (j = 1; (c = (*argv)[j]) != '/0'; j++) { switch (c) { case 'n': numeric = 1; break; case 'r': reverse = 1; break; case 'f': foldul = 1; break; } } } } if ((nlines = readlines(lineptr, MAXLINES)) >= 0) { if (numeric) { mqsort((void **) lineptr, 0, nlines-1, (int (*) (void *, void *))numcmp); } else if (foldul) { mqsort((void **) lineptr, 0, nlines-1, (int (*) (void *, void *))strcmp_ignoreCase); } else { mqsort((void **) lineptr, 0, nlines-1, (int (*) (void *, void *))strcmp); } if (reverse) { reverseF((void **)lineptr, nlines); } writelines(lineptr, nlines); for (i = 0; i < nlines; i++) { if (lineptr[i] != NULL) { free(lineptr[i]); } } return 0; } else { printf("input too big to sort/n"); return 1; }}
开发者ID:imej,项目名称:c,代码行数:54,
示例28: main/* ordena lineas de entrada */int main(){ int nlines; /* numero de lineas de entrada leidas */ if( ( nlines = readlines( lineptr, MAXLINES ) ) >= 0 ){ qsort( lineptr, nlines ); writelines( lineptr, nlines ); return 0; } else { printf( "error: entrada demasiado grade para ordenarla/n" ); return 1; }}
开发者ID:nasciiboy,项目名称:tcpl,代码行数:13,
示例29: mainint main(){ int nlines; char lineread[MAXLEN]; if ((nlines = readlines(lineptr, MAXLINES, lineread)) >= 0){ qsort(lineptr, 0, nlines - 1); writelines(lineptr, nlines); return 0; } else { printf("%s/n", "error: input too big to sort/n"); return 1; }}
开发者ID:ahmaazouzi,项目名称:KR2_Answers,代码行数:13,
示例30: mainint main(int argc, char* argv[]){ int nlines; int numeric = 0; if (argc > 1 && strcmp(argv[1], "/n") == 0) numeric = 1; if ( (nlines = readlines(lineptr, MAXLINES)) >= 0){ myqsort( (void**) lineptr, 0, nlines-1, (int (*)(void*, void*)(numeric ? numcmp : strcmp)) ); writelines(lineptr, nlines); return 0; }
开发者ID:RalfMBecker,项目名称:K-R,代码行数:13,
注:本文中的writelines函数示例整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 C++ writeln函数代码示例 C++ writefifo函数代码示例 |