浅谈linux模拟多线程崩溃和多进程崩溃

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <pthread.h>#include <assert.h>void *fun1(void *arg){ printf("fun1 enter/n"); while(1) {  printf("%s/n", __FUNCTION__);  usleep(1000 * 1000); } printf("fun1 exit/n"); return ((void *)1);}void *fun2(void *arg){ printf("fun1 enter/n"); usleep(1000 * 3000); char * ptr = (char *)malloc(sizeof(char)); printf("ptr1: 0x%x/n", ptr); ptr = NULL; printf("ptr2: 0x%x/n", ptr); free(ptr); memcpy(ptr, "123", 3); printf("ptr3: 0x%x/n", ptr); printf("fun2 exit/n"); return ((void *)2);}int main(void){ pthread_t tid1, tid2; int err;  err = pthread_create(&tid1, NULL, fun1, NULL); assert(0 == err); err = pthread_create(&tid2, NULL, fun2, NULL); assert(0 == err);  printf("main join .../n");// getchar(); pthread_join(tid1, NULL); pthread_join(tid2, NULL);  return 0;}

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <pthread.h>#include <assert.h>void fun(void *arg){ printf("fun1 enter/n"); usleep(1000 * 3000); char * ptr = (char *)malloc(sizeof(char)); printf("ptr1: 0x%x/n", ptr); ptr = NULL; printf("ptr2: 0x%x/n", ptr); free(ptr); memcpy(ptr, "123", 3); printf("ptr3: 0x%x/n", ptr); printf("fun2 exit/n"); return ;}int main(int argc, char *argv[]){ assert(2 == argc); pid_t pid; int i; for(i=0; i<atoi(argv[1]); i++) {  pid = fork();  if(0 > pid)  {   printf("fork error");   exit(1);  }  else if(0 == pid)  {   printf("child pid is %lu/n", (unsigned long)getpid());   fun(NULL);   exit(0);  } }  printf("parent pid is %lu/n", (unsigned long)getpid()); while(-1 != wait(NULL));  //等待所有子进程结束 printf("main return/n"); getchar();  return 0;}