ajax前后端数据交互,前后端json交互,ajax,json交互需求：
前端通过jQuery Ajax传输json到后端，后端接收json，对json进行处理，后端返回一个json给前端 这里使用servlet的方式 1、采用$.post方法
index.jsp页面 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <%@ page contentType="text/html; charset=UTF-8"%> <html> <head> <title></title> <script src="js/jquery-1.12.2.js"></script> <script language="Javascript"> function checkUserid() { $.post('Ajax/CheckServlet',//url { userid : $("#userid").val(), sex : "男" }, function(data) { var obj = eval('(' + data + ')'); alert(obj.success); }); } </script> </head> <body> 用户ID: <input type="text" id="userid" name="userid"> <span id="msg"></span> <br> <button onclick="checkUserid()">传输</button> </body> </html> CheckServlet.Java代码如下 package com.ajax; import java.io.IOException; import java.io.PrintWriter; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class CheckServlet extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { this.doPost(request, response); } public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { /*设置字符集为'UTF-8'*/ request.setCharacterEncoding("UTF-8"); response.setCharacterEncoding("UTF-8"); String userid = request.getParameter("userid"); // 接收userid String sex = request.getParameter("sex");//接收性别 System.out.println(userid); System.out.println(sex); //写返回的JSON PrintWriter pw = response.getWriter(); String json = "{'success':'成功','false':'失败'}"; pw.print(json); pw.flush(); pw.close(); } } 由于这里采用的是servlet的方式，所以要配置web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1"> <display-name>Ajax</display-name> <servlet> <servlet-name>CheckServlet</servlet-name> <servlet-class>com.ajax.CheckServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>CheckServlet</servlet-name> <url-pattern>/Ajax/CheckServlet</url-pattern> </servlet-mapping> </web-app> 在页面输入一个ID，可以在后台接收到并且打印出来，后台通过PrintWriter进行回写JSON返回前端，前端通过eval将JSON变换为Object对象，通过obj.name获取JSON值 2、采用$.get方法，只需要将jsp页面里面的post改为get即可
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <%@ page contentType="text/html; charset=UTF-8"%> <html> <head> <title></title> <script src="js/jquery-1.12.2.js"></script> <script language="Javascript"> function checkUserid() { $.get( 'Ajax/CheckServlet',//url { userid:$("#userid").val(), sex:"男" }, function(data){ var obj = eval('('+data+')'); alert(obj.success); } ); } </script> </head> <body> 用户ID: <input type="text" id="userid" name="userid"> <span id="msg"></span> <br> <button onclick="checkUserid()">传输</button> </body> </html> 结果与$.post一样 3、通过$.ajax方法 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <%@ page contentType="text/html; charset=UTF-8"%> <html> <head> <title></title> <script src="js/jquery-1.12.2.js"></script> <script language="Javascript"> function checkUserid() { $.ajax({ type : 'post', data : { userid : $("#userid").val(), sex : "男" }, url : "Ajax/CheckServlet", success : function(data) { var obj = eval('(' + data + ')'); alert(obj.success); }, error : function() { }, complete : function() { } }); } </script> </head> <body> 用户ID: <input type="text" id="userid" name="userid"> <span id="msg"></span> <br> <button onclick="checkUserid()">传输</button> </body> </html> $.ajax方法也是可以分为post和get方法的，通过修改type来修改发送的方式
结果与方法1是相同的 以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持wanshiok.com。
ajax前后端数据交互,前后端json交互,ajax,json交互
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